Figuring out the day of the week with Luup code

Developer's Corner General Dev Discussions
#1

Hi,

I’m trying to figure out how to determine the day of the week with Luup code (I have an event that fires on week days but I don’t want it to fire at the weekend so the only way I can see to do it is with code, there are no check boxes with an event), can anyone help with this please?

Thanks in advance for your help,

Mark

#2

Try os.date

[url=http://www.lua.org/manual/5.1/manual.html#pdf-os.date]Lua 5.1 Reference Manual

#3

Thanks but still can’f figure out how to extract the day of week out of this. I understand wday is part of a table, I just can’t figure out how to get it out of the table.

Thanks agian for any help. I’m a total newbie as you can tell.

Mark

#4 
local t = os.date ("*t")
local weekdays = {
    "Sunday",
    "Monday",
    "Tuesday",
    "Wednesday",
    "Thursday",
    "Friday",
    "Saturday"
}
luup.log ("Today is day " .. t.wday .. " of the week, which means " .. weekdays[t.wday])

The code above will print:

Today is day 5 of the week, which means Thursday
#5

Thanks much. I was just reading all about tables and had figured out:

– Check to see if it’s the weekend
local dy = os.date(“*t”)
local day_of_week = dy.wday
if (day_of_week == 1) or (day_of_week == 7) then
return false
end

But didn’t know how to assign a name to them so that is helpful.

Thanks again,

Mark

#6 
print(os.date("%A", os.time()))